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@@ -73,7 +73,7 @@ In a hurry? Here's how to do common aggregate queries, assuming the models above
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{'price_per_page': 0.4470664529184653}
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# All the following queries involve traversing the Book<->Publisher
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- # many-to-many relationship backward
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+ # foreign key relationship backwards.
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# Each publisher, each with a count of books as a "num_books" attribute.
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>>> from django.db.models import Count
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@@ -242,7 +242,7 @@ price field of the book model to produce a minimum and maximum value.
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The same rules apply to the ``aggregate()`` clause. If you wanted to
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know the lowest and highest price of any book that is available for sale
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-in a store, you could use the aggregate::
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+in any of the stores, you could use the aggregate::
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>>> Store.objects.aggregate(min_price=Min('books__price'), max_price=Max('books__price'))
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